Formulas For Work And Time

December 3, 2020

Formulas for work and time

Work: When the certain amount of job is assigned  to an individual known as Work

Time: Time is defined as the required duration to complete the task.

Formulas for work and time

Work and Time Formula's

Definition

  • Work: In terms of mathematics work is defined as the amount of job assigned or the amount of job actually done.
  • Time: Time is defined as the number of days or hours required to complete the task

Formula's for Work and Time

Work from Days:

If A can do a piece of work in n days, then A’s one day work = 1n \frac{1}{n}

Days from work:

If A’s one day work = 1n \frac{1}{n}, then A can finish the work in n days

Work Done by A and B

A and B can do a piece of work in ‘a’ days and ‘b’ days respectively.

When working together they will take aba+b \frac{ab}{a+b} days to finish the work

In one day, they will finish (a+bab)th( \frac{a+b}{ab})^{th}  part of work.

Ratio:

If A is thrice as good a workman as B, then:

Ratio of work done by A and B = 3: 1.

Ratio of times taken by A and B to finish a work = 1: 3

Efficiency:

Efficiency is inversely proportional to the

Time taken when the amount of work done is constant.

Efficiency α = 1Time Taken \frac{1}{Time  Taken}

Basic Rules for Work and Time

Rule 1: If A completes a piece of work in x days. And B can completes same piece of work in y days .

Then,

One day work of A = 1x \frac{1}{x} One day work of B = 1y \frac{1}{y}

Work done by A + B = 1x \frac{1}{x} + 1y \frac{1}{y} = x+yxy \frac{x+y}{xy}

Total time = xyx+y \frac{xy}{x + y}

Rule 2: If A completes a piece of work in x days. B completes same piece of work in y days .C completes same piece of work in z days

Then,

One day work of A = 1x \frac{1}{x}

One day work of B = 1y \frac{1}{y}

One day work of C = 1z \frac{1}{z}

Work done by A + B + C = 1x \frac{1}{x} + 1y \frac{1}{y} + 1z \frac{1}{z} = yz+xz+xyxyz \frac{yz+xz+xy}{xyz}

Total time = xyzxy+yz+zx \frac{xyz}{xy + yz + zx}.

Rule 3:  If M1 men can complete a work W1 in D1 days and M2 men can complete a work W2 in D2 days then, M1D1W1 \frac{M_{1}D_{1}}{W_{1}} = M2D2W2 \frac{M_{2}D_{2}}{W_{2}}  .

If Time required by Both M1 and M2 is T1 and T2 respectively, then relation is M1D1T1W1 \frac{M_{1}D_{1}T_{1}}{W_{1}} = M2D2T2W2 \frac{M_{2}D_{2}T_{2}}{W_{2}}

Rule 4:  If A alone can complete a certain work in ‘x’ days and A and B together can do the same amount of work in ‘y’ days,

Work done by b =1/y – 1/x = x-y/xy

Then B alone can do the same work in  xy/(x-y)

 

Rule 5: If A and B can do work in ‘x’ days.

If B and C can do work in ‘y’ days. 

If C and A can do work in ‘z’ days.

Work done by A,B and C = ½ *(1/x+1/y+1/z)

Total time taken when A, B, and C work together xyz/(xy + yz + zx)

Rule 6: Work of one day = Total workTotal number of working days \frac{Total  work}{Total  number  of  working  days}

Total work = one day work × Total number of working days

Remaining work =  1 – work done

Work done by A = A’s one day work × Total number of working days of A

Rule 7:If A can finish mn \frac{m}{n} part of the work in D days.

Then total time taken to finish the work by A = Dmn \frac{D}{\frac{m}{n}} = nm \frac{n}{m} × D days

Rule 8:

If A can do a work in ‘x’ days

B can do the same work in ‘y’ days

When they started working together, B left the work ‘m’ days before completion then total time taken to complete the work = (y+m)x/x+y

Rule 9: A and B finish work in a days.

They work together for ‘b days and then A or B left the work.

B or A finished the rest of the work in ‘d’ days.

Total time taken by A or B alone to complete the work = ada–b \frac{ad}{a – b} or bda−b \frac{bd}{a-b}

Work and Time Formulas & Three Universal Rules

  • If M1 persons can do W1 work in D1 days and M2 persons can do W2 works in D2 days then the formula M1D1W1\frac{M_{1}D_{1}}{W_{1}} =   M2D2W2 \frac{M_{2}D_{2}}{W_{2}} .It can be written as M1D1W2 = M2D2W1.
  • If the persons work T1 and T2 hours per day respectively M1D1T1W1 \frac{M_{1}D_{1}T_{1}}{W_{1}} =  M2D2T2W2 \frac{M_{2}D_{2}T_{2}}{W_{2}}
  • It can be written as, M1D1 T1 W2 = M2D2 T2W1
  • If the persons has efficiency of E1 and E2 respectively then M1D1T1E1W1 \frac{M_{1}D_{1}T_{1}E_{1}}{W_{1}} = M2D2T2E2W2 \frac{M_{2}D_{2}T_{2}E_{2}}{W_{2}} Therefore, M1D1T1E1W2 = M2D2T2E2W1.

In all the above formula,

M = Number of workers

D = Number of days
T = Time required
W = Units of work
E = Efficiency of workers

Read Also â€“ Tips & tricks to solve work and time questions